Decryption of Transposition Cipher
In this chapter, you will learn the procedure for decrypting the transposition cipher.
Code
Observe the following code for a better understanding of decrypting a transposition cipher. The cipher text for message Transposition Cipher with key as 6 is fetched as Toners raiCntisippoh.
import math, pyperclip def main(): myMessage= 'Toners raiCntisippoh' myKey = 6 plaintext = decryptMessage(myKey, myMessage) print("The plain text is") print('Transposition Cipher') def decryptMessage(key, message): numOfColumns = math.ceil(len(message) / key) numOfRows = key numOfShadedBoxes = (numOfColumns * numOfRows) - len(message) plaintext = float('') * numOfColumns col = 0 row = 0 for symbol in message: plaintext[col] += symbol col += 1 if (col == numOfColumns) or (col == numOfColumns - 1 and row >= numOfRows - numOfShadedBoxes): col = 0 row += 1 return ''.join(plaintext) if __name__ == '__main__': main()
Explanation
The cipher text and the mentioned key are the two values taken as input parameters for decoding or decrypting the cipher text in reverse technique by placing characters in a column format and reading them in a horizontal manner.
You can place letters in a column format and later combined or concatenate them together using the following piece of code −
for symbol in message: plaintext[col] += symbol col += 1 if (col == numOfColumns) or (col == numOfColumns - 1 and row >= numOfRows - numOfShadedBoxes): col = 0 row += 1 return ''.join(plaintext)
Output
The program code for decrypting transposition cipher gives the following output −
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